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Hickory Grove Township, Benton County, Indiana

Township in Indiana, United States From Wikipedia, the free encyclopedia

Hickory Grove Township is one of eleven townships in Benton County, Indiana.[3] As of the 2020 census, its population was 398 and it contained 168 housing units.[4] It was organized in March 1876 and named for a grove of hickory trees that grew within its borders in the 19th century.[5]

More information Census, Pop. ...
Historical population
CensusPop.Note%±
1890962—
19001,19123.8%
19101,026−13.9%
19201,1098.1%
1930989−10.8%
1940877−11.3%
1950816−7.0%
1960799−2.1%
1970679−15.0%
1980560−17.5%
1990476−15.0%
2000404−15.1%
20104091.2%
2020398−2.7%
Source: US Decennial Census[6]
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CountryUnited States
OrganizedMarch 1876
Elevation745 ft (227 m)
Quick facts Country, State ...
Hickory Grove Township
Location of Hickory Grove Township in Benton County
Location of Hickory Grove Township in Benton County
Coordinates: 40°31′06″N 87°28′47″W
CountryUnited States
StateIndiana
CountyBenton
OrganizedMarch 1876
Government
 • TypeIndiana township
Area
 • Total
28.9 sq mi (75 km2)
 • Land28.9 sq mi (75 km2)
 • Water0 sq mi (0 km2)
Elevation745 ft (227 m)
Population
 (2020)
 • Total
398
 • Density13.8/sq mi (5.32/km2)
Time zoneUTC-5 (EST)
 • Summer (DST)UTC-4 (EDT)
Area code765
FIPS code18-33358[2]
GNIS feature ID453410
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Geography

According to the 2020 census, the township has a total area of 28.9 square miles (75 km2), all land.[4]

Cities and towns

Unincorporated towns

Adjacent townships

Major highways

Cemeteries

The township contains one cemetery, Totheroh.

References

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