Summarize Timeline Top Qs Fact Check
Base on the preliminary definitions above, one would derive directly the following integral forms of
J
v
(
z
,
w
)
{\displaystyle J_{v}(z,w)}
,
Y
v
(
z
,
w
)
{\displaystyle Y_{v}(z,w)}
:
J
v
(
z
,
w
)
=
J
v
(
z
)
+
1
π
i
(
∫
0
w
e
v
π
i
2
−
i
z
cosh
t
cosh
v
t
d
t
−
∫
0
w
e
i
z
cosh
t
−
v
π
i
2
cosh
v
t
d
t
)
=
J
v
(
z
)
+
1
π
i
(
∫
0
w
cos
(
z
cosh
t
−
v
π
2
)
cosh
v
t
d
t
−
i
∫
0
w
sin
(
z
cosh
t
−
v
π
2
)
cosh
v
t
d
t
−
∫
0
w
cos
(
z
cosh
t
−
v
π
2
)
cosh
v
t
d
t
−
i
∫
0
w
sin
(
z
cosh
t
−
v
π
2
)
cosh
v
t
d
t
)
=
J
v
(
z
)
+
1
π
i
(
−
2
i
∫
0
w
sin
(
z
cosh
t
−
v
π
2
)
cosh
v
t
d
t
)
=
J
v
(
z
)
−
2
π
∫
0
w
sin
(
z
cosh
t
−
v
π
2
)
cosh
v
t
d
t
{\displaystyle {\begin{aligned}J_{v}(z,w)&=J_{v}(z)+{\dfrac {1}{\pi i}}\left(\int _{0}^{w}e^{{\frac {v\pi i}{2}}-iz\cosh t}\cosh vt~dt-\int _{0}^{w}e^{iz\cosh t-{\frac {v\pi i}{2}}}\cosh vt~dt\right)\\&=J_{v}(z)+{\dfrac {1}{\pi i}}\left(\int _{0}^{w}\cos \left(z\cosh t-{\dfrac {v\pi }{2}}\right)\cosh vt~dt-i\int _{0}^{w}\sin \left(z\cosh t-{\dfrac {v\pi }{2}}\right)\cosh vt~dt\right.\\&\quad \quad \quad \quad \quad \quad \left.-\int _{0}^{w}\cos \left(z\cosh t-{\dfrac {v\pi }{2}}\right)\cosh vt~dt-i\int _{0}^{w}\sin \left(z\cosh t-{\dfrac {v\pi }{2}}\right)\cosh vt~dt\right)\\&=J_{v}(z)+{\dfrac {1}{\pi i}}\left(-2i\int _{0}^{w}\sin \left(z\cosh t-{\dfrac {v\pi }{2}}\right)\cosh vt~dt\right)\\&=J_{v}(z)-{\dfrac {2}{\pi }}\int _{0}^{w}\sin \left(z\cosh t-{\dfrac {v\pi }{2}}\right)\cosh vt~dt\end{aligned}}}
Y
v
(
z
,
w
)
=
Y
v
(
z
)
+
1
π
(
∫
0
w
e
v
π
i
2
−
i
z
cosh
t
cosh
v
t
d
t
+
∫
0
w
e
i
z
cosh
t
−
v
π
i
2
cosh
v
t
d
t
)
=
Y
v
(
z
)
+
1
π
(
∫
0
w
cos
(
z
cosh
t
−
v
π
2
)
cosh
v
t
d
t
−
i
∫
0
w
sin
(
z
cosh
t
−
v
π
2
)
cosh
v
t
d
t
+
∫
0
w
cos
(
z
cosh
t
−
v
π
2
)
cosh
v
t
d
t
+
i
∫
0
w
sin
(
z
cosh
t
−
v
π
2
)
cosh
v
t
d
t
)
=
Y
v
(
z
)
+
2
π
∫
0
w
cos
(
z
cosh
t
−
v
π
2
)
cosh
v
t
d
t
{\displaystyle {\begin{aligned}Y_{v}(z,w)&=Y_{v}(z)+{\dfrac {1}{\pi }}\left(\int _{0}^{w}e^{{\frac {v\pi i}{2}}-iz\cosh t}\cosh vt~dt+\int _{0}^{w}e^{iz\cosh t-{\frac {v\pi i}{2}}}\cosh vt~dt\right)\\&=Y_{v}(z)+{\dfrac {1}{\pi }}\left(\int _{0}^{w}\cos \left(z\cosh t-{\dfrac {v\pi }{2}}\right)\cosh vt~dt-i\int _{0}^{w}\sin \left(z\cosh t-{\dfrac {v\pi }{2}}\right)\cosh vt~dt\right.\\&\quad \quad \quad \quad \quad \quad \left.+\int _{0}^{w}\cos \left(z\cosh t-{\dfrac {v\pi }{2}}\right)\cosh vt~dt+i\int _{0}^{w}\sin \left(z\cosh t-{\dfrac {v\pi }{2}}\right)\cosh vt~dt\right)\\&=Y_{v}(z)+{\dfrac {2}{\pi }}\int _{0}^{w}\cos \left(z\cosh t-{\dfrac {v\pi }{2}}\right)\cosh vt~dt\end{aligned}}}
With the Mehler–Sonine integral expressions of
J
v
(
z
)
=
2
π
∫
0
∞
sin
(
z
cosh
t
−
v
π
2
)
cosh
v
t
d
t
{\displaystyle J_{v}(z)={\dfrac {2}{\pi }}\int _{0}^{\infty }\sin \left(z\cosh t-{\dfrac {v\pi }{2}}\right)\cosh vt~dt}
and
Y
v
(
z
)
=
−
2
π
∫
0
∞
cos
(
z
cosh
t
−
v
π
2
)
cosh
v
t
d
t
{\displaystyle Y_{v}(z)=-{\dfrac {2}{\pi }}\int _{0}^{\infty }\cos \left(z\cosh t-{\dfrac {v\pi }{2}}\right)\cosh vt~dt}
mentioned in Digital Library of Mathematical Functions ,[ 2]
we can further simplify to
J
v
(
z
,
w
)
=
2
π
∫
w
∞
sin
(
z
cosh
t
−
v
π
2
)
cosh
v
t
d
t
{\displaystyle J_{v}(z,w)={\dfrac {2}{\pi }}\int _{w}^{\infty }\sin \left(z\cosh t-{\dfrac {v\pi }{2}}\right)\cosh vt~dt}
and
Y
v
(
z
,
w
)
=
−
2
π
∫
w
∞
cos
(
z
cosh
t
−
v
π
2
)
cosh
v
t
d
t
{\displaystyle Y_{v}(z,w)=-{\dfrac {2}{\pi }}\int _{w}^{\infty }\cos \left(z\cosh t-{\dfrac {v\pi }{2}}\right)\cosh vt~dt}
, but the issue is not quite good since the convergence range will reduce greatly to
|
v
|
<
1
{\displaystyle |v|<1}
.