Iridium tetroxide
Chemical compound
From Wikipedia, the free encyclopedia
Iridium tetroxide (IrO4, Iridium(VIII) oxide) is a binary compound of oxygen and iridium in oxidation state +8.[1] This compound was formed by photochemical rearrangement of [(η1-O2)IrO2] in solid argon at a temperature of 6 K (−267.15 °C; −448.87 °F). At higher temperatures, the oxide is unstable.[2] The detection of the iridium tetroxide cation IrO+
4 by infrared photodissociation spectroscopy with formal oxidation state +9 has been reported, the highest currently known of any element.[3][4] However no salts are known, as attempted production of an Ir(IX) salt such as IrO4SbF6 did not result in anything.
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| Names | |
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| IUPAC name
Iridium(VIII) oxide | |
| Identifiers | |
3D model (JSmol) |
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| Properties | |
| IrO4 | |
| Molar mass | 256.213 g·mol−1 |
| Melting point | Decomposes at −267.15 °C (−448.87 °F; 6.00 K) |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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