Jackson Township, Nevada County, Arkansas
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Jackson Township | |
|---|---|
  Jackson Township Location in Arkansas  Jackson Township Jackson Township (the United States) | |
| Coordinates: 33°35′50″N 93°09′30″W / 33.597099°N 93.158403°W[1] | |
| Country | United States |
| State | Arkansas |
| County | Nevada |
| Area | |
• Total | 40.726 sq mi (105.48 km2) |
| • Land | 40.700 sq mi (105.41 km2) |
| • Water | 0.026 sq mi (0.067 km2) |
| Elevation | 331 ft (101 m) |
| Population | |
• Total | 105 |
| • Density | 2.58/sq mi (0.996/km2) |
| Time zone | UTC-6 (CST) |
| • Summer (DST) | UTC-5 (CDT) |
| FIPS code[2][3] | 05-91869 |
| GNIS ID[2][3] | 68903 |
Jackson Township is a township in Nevada County, Arkansas, United States.[4] Its total population was 105 as of the 2010 United States census,[1][5] a decrease of 41.34 percent from 179 at the 2000 census.[6][7]
According to the 2010 Census, Jackson Township is located at 33°35′50″N 93°09′30″W / 33.597099°N 93.158403°W (33.597099, -93.158403).[1] It has a total area of 40.726 square miles (105.48 square kilometers); of which 40.700 sq mi (105.41 km2) is land and 0.026 sq mi (0.067 km2) is water (0.06%).[1] As per the USGS National Elevation Dataset, the elevation is 331 feet (101 m).[2]
