Jacksonville, Iowa

From Wikipedia, the free encyclopedia

CountryUnited States
Elevation1,303 ft (397 m)
Jacksonville, Iowa
Jacksonville, looking east along 1000th street
Jacksonville, looking east along 1000th street
Jacksonville, Iowa is located in Iowa
Jacksonville, Iowa
Jacksonville, Iowa
Coordinates: 41°38′42″N 95°09′06″W / 41.64500°N 95.15167°W / 41.64500; -95.15167
CountryUnited States
StateIowa
CountyShelby
Area
  Total
0.097 sq mi (0.25 km2)
  Land0.097 sq mi (0.25 km2)
  Water0 sq mi (0.00 km2)
Elevation1,303 ft (397 m)
Population
 (2020)
  Total
29
  Density294.9/sq mi (113.85/km2)
Time zoneUTC-6 (Central (CST))
  Summer (DST)UTC-5 (CDT)
ZIP code
51537[3]
Area code712
GNIS feature ID2583483[2]

Jacksonville is an unincorporated community and census-designated place in Jackson Township, Shelby County, Iowa, in the United States. As of the 2020 Census the population of Jacksonville was 29.

Jacksonville was originally built up chiefly by the Danish.[4] Jacksonville's population was 12 in 1902,[5] and 75 in 1925.[6] The population was 50 in 1940.[7]

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