Laketon, Indiana
Census-designated place in Indiana, United States
From Wikipedia, the free encyclopedia
Laketon is an unincorporated census-designated place in Pleasant Township, Wabash County, in the U.S. state of Indiana.[2] As of the 2020 census, Laketon had a population of 606.[4]
Laketon, Indiana | |
|---|---|
Location of Laketon in Wabash County, Indiana. | |
| Coordinates: 40°58′50″N 85°50′22″W | |
| Country | United States |
| State | Indiana |
| County | Wabash |
| Township | Pleasant |
| Area | |
• Total | 1.22 sq mi (3.15 km2) |
| • Land | 1.05 sq mi (2.73 km2) |
| • Water | 0.16 sq mi (0.42 km2) |
| Elevation | 758 ft (231 m) |
| Population (2020) | |
• Total | 606 |
| • Density | 574.9/sq mi (221.97/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 46943 |
| FIPS code | 18-41562[3] |
| GNIS feature ID | 2629856[2] |
