Lee Township, Athens County, Ohio
Township in Ohio, US
From Wikipedia, the free encyclopedia
Lee Township is one of the fourteen townships of Athens County, Ohio, United States. The 2020 census found 2,837 people in the township.[3]
Lee Township, Athens County, Ohio | |
|---|---|
| |
 Location of Lee Township in Athens County | |
| Coordinates: 39°14′23″N 82°13′12″W | |
| Country | United States |
| State | Ohio |
| County | Athens |
| Area | |
• Total | 25.3 sq mi (65.5 km2) |
| • Land | 24.9 sq mi (64.5 km2) |
| • Water | 0.39 sq mi (1.0 km2) |
| Elevation | 781 ft (238 m) |
| Population (2020) | |
• Total | 2,837 |
| • Density | 114/sq mi (44.0/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| FIPS code | 39-42420[2] |
| GNIS feature ID | 1085755[1] |
Geography
Located in the southwestern corner of the county, it borders the following townships:
- Waterloo Township - north
- Athens Township - northeast corner
- Alexander Township - east
- Scipio Township, Meigs County - southeast corner
- Columbia Township, Meigs County - south
- Knox Township, Vinton County - west
Most of the village of Albany is located in southeastern Lee Township.
Name and history
Government
The township is governed by a three-member board of trustees, who are elected in November of odd-numbered years to a four-year term beginning on the following January 1. Two are elected in the year after the presidential election and one is elected in the year before it. There is also an elected township fiscal officer,[5] who serves a four-year term beginning on April 1 of the year after the election, which is held in November of the year before the presidential election. Vacancies in the fiscal officership or on the board of trustees are filled by the remaining trustees.