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Marion Township, Hardin County, Ohio

Township in Ohio, US From Wikipedia, the free encyclopedia

Marion Township is one of the fifteen townships of Hardin County, Ohio, United States. As of the 2020 census the population was 2,301.

CountryUnited States
Elevation968 ft (295 m)
FIPS code39-47712[3]
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Marion Township, Hardin County, Ohio
Farm fields in Marion Township
Farm fields in Marion Township
Location of Marion Township, Hardin County, Ohio
Location of Marion Township, Hardin County, Ohio
Coordinates: 40°41′49″N 83°49′23″W
CountryUnited States
StateOhio
CountyHardin
Area
 • Total
33.2 sq mi (86.0 km2)
 • Land33.2 sq mi (86.0 km2)
 • Water0 sq mi (0.0 km2)
Elevation968 ft (295 m)
Population
 • Total
2,301
 • Density69.3/sq mi (26.8/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
FIPS code39-47712[3]
GNIS feature ID1086266[1]
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Geography

Located in the western part of the county, it borders the following townships:

Two villages are located in Marion Township: Alger in the northwest, and McGuffey in the east.

Name and history

Marion Township was organized in 1856, and named for Francis Marion, an army officer during the American Revolutionary War.[4] It is one of twelve Marion Townships statewide.[5]

Government

The township is governed by a three-member board of trustees, who are elected in November of odd-numbered years to a four-year term beginning on the following January 1. Two are elected in the year after the presidential election and one is elected in the year before it. There is also an elected township fiscal officer,[6] who serves a four-year term beginning on April 1 of the year after the election, which is held in November of the year before the presidential election. Vacancies in the fiscal officership or on the board of trustees are filled by the remaining trustees.

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