Mikhaylov Island
From Wikipedia, the free encyclopedia
LocationAntarctica
Coordinates66°48′S 85°30′E / 66.800°S 85.500°E
Area685 km2 (264 sq mi)
Length41 km (25.5 mi)
| Geography | |
|---|---|
| Location | Antarctica |
| Coordinates | 66°48′S 85°30′E / 66.800°S 85.500°E |
| Area | 685 km2 (264 sq mi) |
| Length | 41 km (25.5 mi) |
| Width | 19 km (11.8 mi) |
| Highest elevation | 240.6 m (789.4 ft) |
| Administration | |
| Administered under the Antarctic Treaty System | |
| Demographics | |
| Population | Uninhabited |
Mikhaylov Island is an ice-covered non erupted Volcano in the West Ice Shelf of Antarctica, rising to 240 metres (800 ft), 11 kilometres (6 nmi) southeast of Leskov Island. It was discovered by the Soviet Expedition Team in 1956 who chose to name it after Pavel N. Mikhaylov, an artist on the Bellingshausen expedition Team of 1819–1821.[1]