Montmahoux

Commune in Bourgogne-Franche-Comté, France From Wikipedia, the free encyclopedia

Montmahoux (French pronunciation: [mɔ̃ma.u]) is a commune in the Doubs department in the Bourgogne-Franche-Comté region in eastern France.

CountryFrance
Area
1
6.52 km2 (2.52 sq mi)
Population
(2023)[2]
94
Quick facts Country, Region ...
Montmahoux
An aerial view of Montmahoux
An aerial view of Montmahoux
Coat of arms of Montmahoux
Location of Montmahoux
Montmahoux is located in France
Montmahoux
Montmahoux
Montmahoux is located in Bourgogne-Franche-Comté
Montmahoux
Montmahoux
Coordinates: 46°59′03″N 6°02′06″E
CountryFrance
RegionBourgogne-Franche-Comté
DepartmentDoubs
ArrondissementBesançon
CantonOrnans
IntercommunalityLoue-Lison
Government
  Mayor (20202026) Vincent Marguet[1]
Area
1
6.52 km2 (2.52 sq mi)
Population
 (2023)[2]
94
  Density14/km2 (37/sq mi)
Time zoneUTC+01:00 (CET)
  Summer (DST)UTC+02:00 (CEST)
INSEE/Postal code
25404 /25270
Elevation550–823 m (1,804–2,700 ft)
1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km2 (0.386 sq mi or 247 acres) and river estuaries.
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Geography

Montmahoux lies 8 km (5.0 mi) south of Amancey on the edge of the gorge of the Boz.

Population

More information Year, Pop. ...
Historical population
YearPop.±%
196290    
1968106+17.8%
197595−10.4%
198276−20.0%
199080+5.3%
199967−16.2%
200880+19.4%
2012105+31.2%
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See also

References

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