Motukauri Island (Bay of Islands)

From Wikipedia, the free encyclopedia

Coordinates35°15′00.9″S 174°11′06″E / 35.250250°S 174.18500°E / -35.250250; 174.18500
Length374 m (1227 ft)
Width142 m (466 ft)
Motukauri Island
Motukauri Island in front of Manawaora Bay
Motukauri Island is located in Northland Region
Motukauri Island
Motukauri Island
Geography
LocationBay of Islands
Coordinates35°15′00.9″S 174°11′06″E / 35.250250°S 174.18500°E / -35.250250; 174.18500
Length374 m (1227 ft)
Width142 m (466 ft)
Administration
New Zealand
Putahataha Island, location within the Bay Of Islands, Northland Region, New Zealand
Putahataha Island, Bay Of Islands, Northland NZ

Motukauri Island is a small island in the Bay of Islands of New Zealand, located about 6 kilometres (3.7 mi) east of Russell.[1] It lies about 200 kilometres (120 mi) off the Orokawa Peninsula.

Moto translates to Island[2] and kauri refers to the Agathis Tree - also known as the Kauri.[3]

There are three other islands named Motukauri in the Northland Region - most likely due to the meaning of the name in Maori:

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