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Oak Grove Township, Benton County, Indiana

Township in Indiana, United States From Wikipedia, the free encyclopedia

Oak Grove Township is one of eleven townships in Benton County, Indiana. As of the 2020 census, its population was 1,551 and it contained 690 housing units.[3] It was one of the first three townships originally created by the county's commissioners in 1840.[4] It takes its name from White Oak Grove which grew southwest of Oxford.[5]

More information Census, Pop. ...
Historical population
CensusPop.Note%±
18901,495—
19001,67512.0%
19101,603−4.3%
19201,522−5.1%
19301,430−6.0%
19401,220−14.7%
19501,41015.6%
19601,62115.0%
19701,6290.5%
19801,81011.1%
19901,641−9.3%
20001,6943.2%
20101,581−6.7%
20201,551−1.9%
Source: US Decennial Census[6]
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Country United States
OrganizedJuly 1840
Elevation748 ft (228 m)
Quick facts Country, State ...
Oak Grove Township
Location of Oak Grove Township in Benton County
Location of Oak Grove Township in Benton County
Coordinates: 40°31′09″N 87°15′54″W
Country United States
State Indiana
CountyBenton
OrganizedJuly 1840
Government
 • TypeIndiana township
Area
 • Total
35.53 sq mi (92.0 km2)
 • Land35.51 sq mi (92.0 km2)
 • Water0.02 sq mi (0.052 km2)
Elevation748 ft (228 m)
Population
 (2020)
 • Total
1,551
 • Density43.6/sq mi (16.8/km2)
Time zoneUTC-5 (EST)
 • Summer (DST)UTC-4 (EDT)
FIPS code18-55620[2]
GNIS feature ID453681
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Geography

According to the 2020 census, the township has a total area of 35.53 square miles (92.0 km2), of which 35.51 square miles (92.0 km2) (or 99.94%) is land and 0.02 square miles (0.052 km2) (or 0.06%) is water.[3]

Cities and towns

Unincorporated towns

Adjacent townships

Major highways

Cemeteries

The township contains two cemeteries: Justus and Oxford.

References

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