Palladium tetrafluoride
Chemical compound
From Wikipedia, the free encyclopedia
Palladium (IV) fluoride, also known as palladium tetrafluoride, is the chemical compound of palladium and fluorine with the chemical formula PdF4. The palladium atoms in PdF4 are in the +4 oxidation state.[2][3]
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| Identifiers | |
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3D model (JSmol) |
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| ChemSpider | |
PubChem CID |
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| Properties | |
| F4Pd | |
| Molar mass | 182.41 g·mol−1 |
| Appearance | pink[1] or brick-red[2] crystalline solid |
| Related compounds | |
Other cations |
Platinum(IV) fluoride |
Related compounds |
Palladium(II) fluoride Palladium(II,IV) fluoride |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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Structure
Crystals are composed of octahedral PdF6 units, with four fluorides from each octahedron shared (bridging between octahedra).[4]
Synthesis
Palladium tetrafluoride has been prepared by reacting palladium(II,IV) fluoride with fluorine gas at pressures around 7 atm and at 300 °C for several days.[1]
Reactivity
PdF4 is a strong oxidising agent and undergoes rapid hydrolysis in moist air.[1]