Platinum(IV) iodide
Chemical compound
From Wikipedia, the free encyclopedia
Platinum(IV) iodide is an inorganic compound with the formula PtI4.[2] it is a dark brown diamagnetic solid and is one of several binary iodides of platinum.
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| Names | |
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| IUPAC name
tetraiodoplatinum | |
| Other names
Platinum tetraiodide, platinic iodide, platinum(4+) tetraiodide | |
| Identifiers | |
3D model (JSmol) |
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| ChemSpider | |
| ECHA InfoCard | 100.029.280 |
| EC Number |
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PubChem CID |
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| UNII | |
CompTox Dashboard (EPA) |
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| Properties | |
| I4Pt | |
| Molar mass | 702.702 g·mol−1 |
| Appearance | brown crystals |
| Density | 6.06 g/cm3 |
| Melting point | 130 °C (266 °F; 403 K) |
| decomposes | |
| Solubility | soluble in ethanol, acetone, alkali, HI, KI, liquid NH3.[1] |
| Related compounds | |
Related compounds |
Iridium tetraiodide |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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Structure
Platinum(IV) iodide forms dark brown crystals of several modifications:[3]
- α-PtI4, rhombic crystal system, spatial group P bca,[4] cell parameters a = 1.290 nm, b = 1.564 nm, c = 0.690 nm, Z = 8;
- β-PtI4, cubic crystal system, spatial group P m3m, cell parameters a = 0.56 nm, Z = 1;
- γ-PtI4, tetragonal crystal system, spatial group I 41/a, cell parameters a = 0.677 nm, c = 3.110 nm, Z = 8.
Preparation
Chemical properties
It decomposes when heated:
- PtI4 → Pt + 2I2
When dissolved in hydroiodic acid, platinum(IV) iodide forms hydrogen hexaiodoplatinate(IV):
- PtI4 + 2HI → H2[PtI6]