Rajno Polje
From Wikipedia, the free encyclopedia
Rajno Polje | |
|---|---|
 | |
  Rajno Polje | |
| Coordinates: 43°00′38″N 22°04′23″E / 43.01056°N 22.07306°E | |
| Country |  Serbia |
| District | Jablanica District |
| Municipality | Leskovac |
| Population (2002) | |
• Total | 739 |
| Time zone | UTC+1 (CET) |
| • Summer (DST) | UTC+2 (CEST) |
Rajno Polje is a village in the municipality of Leskovac, Serbia. In the 2002 census the population was 739 people.[1]
