Samarium(III) oxyiodide
Chemical compound
From Wikipedia, the free encyclopedia
Samarium(III) oxyiodide is an inorganic compound with the chemical formula SmOI. It can be obtained by reacting samarium(II) iodide with dry oxygen.[2] It is oxidized when heated to 335 °C in air, and starts to generate nSmOI·Sm2O3 (n is 7, 4, 2 respectively) at 460 °C, 560 °C, and 640 °C, and completely transforms at 885 °C for samarium oxide.[3] It can catalyze the rearrangement of propylene oxide derivatives to methyl ketones.[2] It reacts with samarium(III) iodide, sodium iodide, and sodium at 903 K in a tantalum container to obtain black Sm4OI6.[4]
| Names | |
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| Other names
Samarium iodide oxide | |
| Identifiers | |
3D model (JSmol) |
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| Properties | |
| IOSm | |
| Molar mass | 293.26 g·mol−1 |
| Appearance | light milky yellow solid[1] |
| Related compounds | |
Other anions |
Samarium oxysulfide Samarium oxychloride |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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