Samarium(III) phosphate

Samarium(III) phosphate can be obtained by reacting sodium metaphosphate with any soluble samarium(III) salt:

${\displaystyle {\mathsf {SmCl_{3}+NaPO_{3}+H_{2}O\ {\xrightarrow {}}\ 2SmPO_{4}\downarrow +NaCl+2HCl}}}$

Samarium(III) phosphate can also be obtained by reacting phosphoric acid and samarium(III) chloride.^[1]

Samarium(III) phosphate reacts with sodium fluoride at 750 °C to form Na₂SmF₂PO₄.^[2] Samarium(III) phosphate forms crystals of the monoclinic crystal system, with space group P2₁/n, and lattice parameters a = 0.6669 nm, b = 0.6868 nm, c = 0.6351 nm, β = 103.92 °, Z = 4.^[3]