San Andrés Yutatío
Town in Oaxaca, Mexico
From Wikipedia, the free encyclopedia
San Andrés Yutatío is a small town in the municipality of Tezoatlán de Segura y Luna, in the Huajuapan District of the Mixteca Baja region, in the state of Oaxaca, Mexico.[1]
San Andrés Yutatío | |
|---|---|
| Coordinates: 17°36′28″N 97°53′39″W | |
| Country |  Mexico |
| State | Oaxaca |
| Elevation | 2,000 m (6,600 ft) |
| Population (2010 INEGI) | |
• Total | 695 |
| Time zone | UTC-6 (Central Standard Time) |
| • Summer (DST) | UTC-5 (Central Daylight Time) |
Demographics
San Andrés Yutatío has a population of 695 inhabitants according to data from the INEGI Population and Housing Census of 2010. Of these, 320 are men and 375 are women.[2] In 2020 population rose to 823 inhabitants, with 449 being women and 374 being men.