Sand Creek Township, Jennings County, Indiana

From Wikipedia, the free encyclopedia

CountryUnited States
Elevation
725 ft (221 m)
GNIS feature ID0453833
Sand Creek Township
Location in Jennings County
Location in Jennings County
Coordinates: 39°05′16″N 85°36′25″W / 39.08778°N 85.60694°W / 39.08778; -85.60694
CountryUnited States
StateIndiana
CountyJennings
Government
  TypeIndiana township
Area
  Total
27.95 sq mi (72.4 km2)
  Land27.72 sq mi (71.8 km2)
  Water0.23 sq mi (0.60 km2)  0.82%
Elevation
725 ft (221 m)
Population
 (2020)
  Total
859
  Density31.0/sq mi (12.0/km2)
GNIS feature ID0453833

Sand Creek Township is one of eleven townships in Jennings County, Indiana, United States. As of the 2020 census, its population was 859 (down from 872 at 2010[1]) and it contained 364 housing units.[2]

Historical population
CensusPop.Note
18901,039
1900992−4.5%
1910819−17.4%
1920687−16.1%
1930529−23.0%
194061416.1%
1950602−2.0%
19606457.1%
197075216.6%
19808036.8%
1990714−11.1%
200081814.6%
20108726.6%
2020859−1.5%
Source: US Decennial Census[3]

Unincorporated towns

References

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