Sandusky, Iowa
From Wikipedia, the free encyclopedia
Sandusky, Iowa | |
|---|---|
The United Methodist Church in Sandusky | |
| Coordinates: 40°27′52″N 91°23′13″W / 40.46444°N 91.38694°W | |
| Country | USA |
| State | Iowa |
| County | Lee |
| Townships | Jackson Montrose |
| Area | |
• Total | 2.67 sq mi (6.91 km2) |
| • Land | 1.42 sq mi (3.69 km2) |
| • Water | 1.24 sq mi (3.22 km2) |
| Elevation | 543 ft (166 m) |
| Population (2020) | |
• Total | 297 |
| • Density | 208.4/sq mi (80.45/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP Code | 52632 (Keokuk) |
| Area code | 319 |
| FIPS code | 19-70545 |
| GNIS feature ID | 2804144[2] |
Sandusky is an unincorporated community and census-designated place (CDP) in Lee County, Iowa, United States. It is in the southeast part of the county, on the west bank of the Mississippi River 4 miles (6 km) north of Keokuk, the county seat, and 6 miles (10 km) south of Montrose.
Sandusky was first listed as a CDP prior to the 2020 census. As of the 2020 census, its population was 297.[3]
