Sandusky, Iowa

From Wikipedia, the free encyclopedia

CountryUSA
Elevation543 ft (166 m)
Sandusky, Iowa
The United Methodist Church in Sandusky
The United Methodist Church in Sandusky
Sandusky is located in Iowa
Sandusky
Sandusky
Sandusky is located in the United States
Sandusky
Sandusky
Coordinates: 40°27′52″N 91°23′13″W / 40.46444°N 91.38694°W / 40.46444; -91.38694
CountryUSA
StateIowa
CountyLee
TownshipsJackson
Montrose
Area
  Total
2.67 sq mi (6.91 km2)
  Land1.42 sq mi (3.69 km2)
  Water1.24 sq mi (3.22 km2)
Elevation543 ft (166 m)
Population
 (2020)
  Total
297
  Density208.4/sq mi (80.45/km2)
Time zoneUTC-6 (Central (CST))
  Summer (DST)UTC-5 (CDT)
ZIP Code
52632 (Keokuk)
Area code319
FIPS code19-70545
GNIS feature ID2804144[2]

Sandusky is an unincorporated community and census-designated place (CDP) in Lee County, Iowa, United States. It is in the southeast part of the county, on the west bank of the Mississippi River 4 miles (6 km) north of Keokuk, the county seat, and 6 miles (10 km) south of Montrose.

Sandusky was first listed as a CDP prior to the 2020 census. As of the 2020 census, its population was 297.[3]

2020 census

History

References

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