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Sepulga River

From Wikipedia, the free encyclopedia

CountryUnited States
StateAlabama
coordinates31°35′54″N 86°57′12″W / 31.59821°N 86.95331°W / 31.59821; -86.95331
elevation85 ft (26 m)
Sepulga River
Location
CountryUnited States
StateAlabama
Physical characteristics
Source 
 • coordinates31°35′54″N 86°57′12″W / 31.59821°N 86.95331°W / 31.59821; -86.95331
 • elevation85 ft (26 m)
Mouth 
 • location
Conecuh River
 • coordinates
31°10′53″N 86°45′50″W / 31.18128°N 86.76385°W / 31.18128; -86.76385
Length61.5 mi (99.0 km)

The Sepulga River is a 61.5-mile-long (99.0 km)[1] river in the U.S. state of Alabama. It originates at the confluence of the East Sepulga and West Sepulga rivers and discharges into the Conecuh River near the northwestern border of Conecuh National Forest.[2] The name Sepulga is possibly of either Creek or Choctaw origin. If Creek, it is possibly from asi meaning "yaupon" and algi meaning "grove". If Choctaw in origin, the name is possibly derived from shoboli, which means "smoky".[3]

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