Sherman Township, Hardin County, Iowa
Township in Iowa, United States
From Wikipedia, the free encyclopedia
Sherman Township is a township located in Hardin County, Iowa. As of the 2010 Census, its population was 738.[4][1]
Sherman Township | |
|---|---|
 Interactive map of Sherman Township | |
| Coordinates: 42°20′23″N 093°24′17″W | |
| Country |  United States |
| State |  Iowa |
| County | Hardin |
| Area | |
• Total | 35.98 sq mi (93.19 km2) |
| • Land | 35.98 sq mi (93.19 km2) |
| • Water | 0 sq mi (0 km2) |
| Elevation | 1,142 ft (348 m) |
| Population (2000) | |
• Total | 461 |
| • Density | 13/sq mi (5.1/km2) |
| FIPS code | 468 697[2][3] |
| GNIS feature ID | 0468696 |
History
Sherman Township was founded in 1870.[5] It is named for William Tecumseh Sherman.[6]