Siege of Amritsar (1748)

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DateMarch 1748
Location
Result Sikh victory
Siege of Amritsar
Part of Mughal-Sikh Wars
DateMarch 1748
Location
Result Sikh victory
Belligerents
Dal Khalsa Mughal Empire
Commanders and leaders
Nawab Kapur Singh
Jassa Singh Ahluwalia
Tara Singh Waeeyan
Chuhar Singh Bhakniya
Salabat Khan 
Nijabat Khan 
Qutab-ud-Din 
Strength
Unknown Unknown
Casualties and losses
Unknown Unknown

The siege of Amritsar was a siege that took place in March 1748. The Battle was fought between the Sikhs led by Nawab Kapur Singh against the Mughal Forces led by Salabat Khan. The Sikhs successfully defeated and killed Salabat Khan and conquered the city of Amritsar from the Mughals.

After the execution of Bhai Mani Singh, control over the city of Amritsar was taken by the Mughal Empire.[1] The first person in charge of the city was Qazi Abdul Rehman Khan who was killed while fighting the Sikhs in a battle.[2] The second was Massa Ranghar who was assassinated by Sukha Singh and Mehtab Singh Bhangu.[3][4] In 1747, a Muslim Rajput named Salabat Khan was appointed the 3rd person to be in charge of the city of Amritsar.[5] The Mughal Empire was preoccupied with the invasion of Ahmad Shah Abdali, thus the Sikhs took the opportunity to retake Amritsar.[6]

Battle

Nawab Kapur Singh promoted Jassa Singh Ahluwalia as the main commander to lead the campaign.They along with Tara Singh Waeeyan, Chuhar Singh Bhakniya and their armies besieged Amritsar.[6] Jassa Singh Ahluwalia marched towards Salabat Khan and beheaded him with his Khanda.[7][8] His nephew Nijabat Khan attacked Jassa Singh but Nawab Kapur Singh killed him.[1] Another commander named Qutab-ud-Din was slain by the Sikhs.[9] After the death of the Mughal commanders, the Mughal army was routed.[1]

Aftermath

References

See also

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