Sperry, Iowa

From Wikipedia, the free encyclopedia

CountryUnited States
Elevation751 ft (229 m)
Sperry, Iowa
An aerial photograph of Sperry
An aerial photograph of Sperry
Sperry is located in Iowa
Sperry
Sperry
Location within the state of Iowa
Sperry is located in the United States
Sperry
Sperry
Sperry (the United States)
Coordinates: 40°57′26″N 91°09′20″W / 40.95722°N 91.15556°W / 40.95722; -91.15556
CountryUnited States
StateIowa
CountyDes Moines
Area
  Total
2.24 sq mi (5.80 km2)
  Land2.24 sq mi (5.79 km2)
  Water0 sq mi (0.00 km2)
Elevation751 ft (229 m)
Population
 (2020)
  Total
124
  Density55/sq mi (21.4/km2)
Time zoneUTC-6 (Central (CST))
  Summer (DST)UTC-5 (CDT)
ZIP codes
52650
Area code319
FIPS code19-74325
GNIS feature ID2804129[2]

Sperry is an unincorporated community and census-designated place in central Des Moines County, Iowa, United States. It lies along local roads north of the city of Burlington, the county seat of Des Moines County.[3] Its elevation is 751 feet (229 m).[4] Although Sperry is unincorporated, it has a post office with the ZIP code of 52650,[5] which opened on 5 February 1870.[6]

As of the 2020 census, Sperry had a population of 124.[7]

The community is part of the Burlington, IAIL Micropolitan Statistical Area.

2020 census

History

References

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