Spiceland Township, Henry County, Indiana
Township in Indiana, United States
From Wikipedia, the free encyclopedia
Spiceland Township is one of thirteen townships in Henry County, Indiana, United States. As of the 2010 census, its population was 2,279 and it contained 991 housing units.[2]
Spiceland Township | |
|---|---|
Location in Henry County | |
| Coordinates: 39°49′12″N 85°27′12″W | |
| Country | United States |
| State | Indiana |
| County | Henry |
| Government | |
| • Type | Indiana township |
| Area | |
• Total | 22.32 sq mi (57.8 km2) |
| • Land | 22.22 sq mi (57.5 km2) |
| • Water | 0.09 sq mi (0.23 km2) 0.40% |
| Elevation | 1,040 ft (317 m) |
| Population | |
• Total | 2,184 |
| • Density | 102.5/sq mi (39.6/km2) |
| GNIS feature ID | 0453862 |
Spiceland Township was organized in 1842.[3] It was named from the growth of spice bushes within its borders.[3]
Geography
According to the 2010 census, the township has a total area of 22.32 square miles (57.8 km2), of which 22.22 square miles (57.5 km2) (or 99.55%) is land and 0.09 square miles (0.23 km2) (or 0.40%) is water.[2]
Cities and towns
Unincorporated towns
(This list is based on USGS data and may include former settlements.)
Adjacent townships
- Henry Township (northeast)
- Franklin Township (east)
- Center Township, Rush County (south)
- Wayne Township (west)
- Greensboro Township (northwest)
Major highways
Education
Spiceland Township residents are served by the Spiceland Town-Township Public Library.[4]