Suslovo
From Wikipedia, the free encyclopedia
Suslovo
Суслово | |
|---|---|
Selo | |
| Coordinates: 55°25′N 55°42′E / 55.417°N 55.700°E[1] | |
| Country | Russia |
| Region | Bashkortostan |
| District | Birsky District |
| Time zone | UTC+5:00 |
Suslovo (Russian: Суслово) is a rural locality (a selo) and the administrative centre of Suslovsky Selsoviet, Birsky District, Bashkortostan, Russia. The population was 647 as of 2010.[2] There are 13 streets.