Trey Phillips (tennis)
From Wikipedia, the free encyclopedia
Country(sports)
United States
United StatesBornJune 27, 1973
Austin, Texas, U.S.
Austin, Texas, U.S.
Height6 ft 6 in (198 cm)
Prize money$14,590
| Country (sports) | United States |
|---|---|
| Born | June 27, 1973 Austin, Texas, U.S. |
| Height | 6 ft 6 in (198 cm) |
| Prize money | $14,590 |
| Singles | |
| Highest ranking | No. 772 (June 24, 1996) |
| Doubles | |
| Career record | 0–5 |
| Highest ranking | No. 154 (June 9, 1997) |
| Grand Slam doubles results | |
| Wimbledon | Q1 (1997) |
Trey Phillips (born June 27, 1973) is an American former professional tennis player.
Phillips grew up in Austin, Texas and won state tennis titles at Westlake High School.[1]
A three-time All-American at the University of Texas, Phillips went on to compete on the professional tour and was ranked as high as 154 in the world in doubles. He won one ATP Challenger doubles title.
Phillips now works as a real estate agent in Austin.[2]
