Tsankov Island
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  Tsankov Island Location of Tsankov Island  Tsankov Island Tsankov Island (Antarctic Peninsula) | |
| Geography | |
|---|---|
| Location | Antarctica |
| Coordinates | 65°03′58″S 64°08′38″W / 65.06611°S 64.14389°W |
| Archipelago | Wilhelm Archipelago |
| Area | 9.48 ha (23.4 acres) |
| Length | 625 m (2051 ft) |
| Width | 216 m (709 ft) |
| Administration | |
| Administered under the Antarctic Treaty System | |
| Demographics | |
| Population | uninhabited |
Tsankov Island (Bulgarian: Цанков остров, romanized: Tsankov ostrov, IPA: [t͡sɐnˈkɔf ˈɔstrof]) is the mostly ice-covered island 625 m long in west-southwest to west-northeast direction and 216 m wide in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 9.48 ha.[1]
The feature is named after the dermatologist Nikolay Tsankov, participant in the 2010/11 and subsequent Bulgarian Antarctic campaigns.[1]
Tsankov Island is located at 65°03′58″S 64°08′38″W / 65.06611°S 64.14389°W, which is 293 m northwest of Stego Island, 175 m east of Bodloperka Island, 1.18 km southeast of Sprey Island and 1.25 km west-southwest of Taralezh Island. British mapping in 2001.
Maps
- British Admiralty Nautical Chart 446 Anvers Island to Renaud Island. Scale 1:150000. Admiralty, UK Hydrographic Office, 2001
- Brabant Island to Argentine Islands. Scale 1:250000 topographic map. British Antarctic Survey, 2008
- Antarctic Digital Database (ADD). Scale 1:250000 topographic map of Antarctica. Scientific Committee on Antarctic Research (SCAR). Since 1993, regularly upgraded and updated
