User:TheTallOne/TeX

This was my first go at using TeX and this went towards my Maths GCSE.

<table class="toccolours" border="1" cellpadding="4" style="float: right; margin: 0 0 1em 1em; border-collapse: collapse; font-size: 95%; clear: right">
<tr>
<th>Qualification</th>
<th>Subject</th>
<th>Grade</th>
</tr>
<tr>
<td>GCSE</td>
<td>Religious Studies B Module 1</td>
<td>A* (90%)</td>
</tr>
</table>

${\displaystyle SD={\sqrt {\frac {\Sigma \ {\big (}x-{\overline {x}}\ {\big )}^{2}}{n}}}}$

${\displaystyle StandardDeviation={\sqrt {\frac {\Sigma \ {\big (}x-{\overline {x}}\ {\big )}^{2}}{n}}}}$

And this is my second go...es

${\displaystyle A={\frac {1}{2}}bh\times n}$

${\displaystyle A={\frac {1}{2}}\times {\Bigg (}{\frac {1000}{n}}{\Bigg )}hn}$

${\displaystyle A={\frac {1}{2}}}$

${\displaystyle A={\Bigg (}{\frac {1000}{2n}}{\Bigg )}\times {\frac {1000}{\left[2n\tan \left({\frac {360}{2n}}\right)\right]}}}$

${\displaystyle b={\frac {p}{n}}}$

${\displaystyle x={\frac {360}{2n}}}$

${\displaystyle O={\frac {p}{2n}}}$

${\displaystyle \tan x={\frac {O}{A}}}$

${\displaystyle \tan {\frac {360}{2n}}={\frac {\frac {p}{2n}}{A}}}$

${\displaystyle A\tan {\Bigg (}{\frac {360}{2n}}{\Bigg )}={\frac {p}{2n}}}$

${\displaystyle A={\frac {p}{2n}}\times {\frac {1}{\left[\tan \left({\frac {360}{2n}}\right)\right]}}}$

${\displaystyle A={\frac {p}{\left[2n\tan \left({\frac {360}{2n}}\right)\right]}}}$

${\displaystyle h={\frac {p}{\left[2n\tan \left({\frac {360}{2n}}\right)\right]}}}$

${\displaystyle A={\frac {1}{2}}\times {\frac {p}{n}}\times {\frac {p}{\left[2n\tan \left({\frac {360}{2n}}\right)\right]}}\times n}$

${\displaystyle A={\frac {p^{2}}{4n\tan \left({\frac {180}{n}}\right)}}}$

${\displaystyle p=2\pi r\,}$

${\displaystyle r={\frac {p}{2\pi }}\,}$

${\displaystyle A=\pi r^{2}\,}$

${\displaystyle A=\pi \times \left({\frac {p}{2\pi }}\right)^{2}}$

${\displaystyle A=\pi \times \left({\frac {p^{2}}{4\pi ^{2}}}\right)}$

${\displaystyle A={\frac {p^{2}}{4\pi }}}$

${\displaystyle {\frac {p^{2}}{4n\tan \left({\frac {180}{n}}\right)}}<{\frac {p^{2}}{4\pi }}}$

${\displaystyle n\tan \left({\frac {180}{n}}\right)<\pi }$