Van Buren Township, Shelby County, Indiana
Township in Indiana, United States
From Wikipedia, the free encyclopedia
Van Buren Township is one of fourteen townships in Shelby County, Indiana. As of the 2010 census, its population was 1,480 and it contained 622 housing units.[4]
Van Buren Township | |
|---|---|
| |
| Coordinates: 39°39′43″N 85°47′31″W | |
| Country | United States |
| State | Indiana |
| County | Shelby |
| Government | |
| • Type | Indiana township |
| Area | |
• Total | 27.91 sq mi (72.3 km2) |
| • Land | 27.9 sq mi (72 km2) |
| • Water | 0.01 sq mi (0.026 km2) |
| Elevation | 837 ft (255 m) |
| Population | |
• Total | 1,452 |
| • Density | 53/sq mi (20/km2) |
| FIPS code | 18-78578[3] |
| GNIS feature ID | 453952 |
The township was named for Martin Van Buren, the eighth President of the United States.[5]
Geography
According to the 2010 census, the township has a total area of 27.91 square miles (72.3 km2), of which 27.9 square miles (72 km2) (or 99.96%) is land and 0.01 square miles (0.026 km2) (or 0.04%) is water.[4]
