Vanadium(II) fluoride
Chemical compound
From Wikipedia, the free encyclopedia
Vanadium(II) fluoride is a fluoride of vanadium, with the chemical formula of VF2. It forms blue crystals.
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| Names | |
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| Other names
Vanadium(II) fluoride | |
| Identifiers | |
3D model (JSmol) |
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PubChem CID |
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| Properties | |
| F2V | |
| Molar mass | 88.9383 g·mol−1 |
| Appearance | deep blue crystals[1] |
| Density | 3.954 g/cm3[1] |
| soluble in water, forms [V(H2O)6]2+[2] | |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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Structure
Vanadium(II) fluoride crystallizes in the tetragonal crystal system with space group P42/mnm (No. 136). Its lattice constants are a = 480.4 pm and c = 323.7 pm.[1]
Preparation
Vanadium(II) fluoride can be produced by the reduction of vanadium trifluoride by hydrogen in a hydrogen fluoride atmosphere at 1150 °C:[3]
- 2 VF3 + H2 → 2 VF2 + 2 HF
Reactions
Vanadium(II) fluoride is a strong reducing agent that can reduce nitrogen to hydrazine in the presence of magnesium hydroxide.[2]
It dissolves in water to form [V(H2O)6]2+ ions.[2]
- V2+ + 6 H2O → [V(H2O)6]2+