Vanadium(II) iodide
Chemical compound
From Wikipedia, the free encyclopedia
Vanadium(II) iodide is the inorganic compound with the formula VI2. It is a black micaceous solid. It adopts the cadmium iodide structure, featuring octahedral V(II) centers.[2] The hexahydrate [V(H2O)6]I2, an aquo complex, is also known. It forms red-violet crystals. The hexahydrate dehydrates under vacuum to give a red-brown tetrahydrate with the formula V(H2O)4I2.[3]
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3D model (JSmol) |
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| ChemSpider | |
| ECHA InfoCard | 100.035.935 |
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PubChem CID |
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CompTox Dashboard (EPA) |
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| Properties | |
| VI2 | |
| Appearance | black mica-like |
| Density | 5.44 g/cm3[1] |
| Melting point | 750–800 °C (1,380–1,470 °F; 1,020–1,070 K)[1] (sublimes) |
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Other anions |
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Related compounds |
Vanadium(III) iodide |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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Preparation
The original synthesis of VI2 involved reaction of the elements.[2]
Solvated vanadium(II) iodides can be prepared by reduction of vanadium(III) chlorides with trimethylsilyl iodide.[4] It reacts with anhydrous ammonia to give the hexaammine complex.[5]