Wolfhurst, Ohio
Census-designated place in Ohio, United States
From Wikipedia, the free encyclopedia
Wolfhurst is a census-designated place (CDP) in Belmont County, Ohio, United States. It is part of the Wheeling, West Virginia Metropolitan Statistical Area. The population was 1,119 at the 2020 census.
Wolfhurst, Ohio | |
|---|---|
  Wolfhurst Location within Ohio | |
| Coordinates: 40°04′08″N 80°46′52″W | |
| Country | United States |
| State | Ohio |
| County | Belmont |
| Area | |
• Total | 0.50 sq mi (1.30 km2) |
| • Land | 0.48 sq mi (1.25 km2) |
| • Water | 0.015 sq mi (0.04 km2) |
| Elevation | 676 ft (206 m) |
| Population (2020) | |
• Total | 1,119 |
| • Density | 2,313.1/sq mi (893.09/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| Area code | 740 |
| FIPS code | 39-86282[3] |
| GNIS feature ID | 2628989[2] |
Geography
Wolfhurst is located in eastern Belmont County in the valley of Wheeling Creek. It is bordered to the northwest by Lansing, and the village of Brookside is 1 mile (1.6 km) to the east. U.S. Route 40, the National Road, passes through the center of Wolfhurst, leading east 4 miles (6 km) to downtown Wheeling, West Virginia.
According to the United States Census Bureau, the Wolfhurst CDP has a total area of 0.50 square miles (1.30 km2), of which 0.015 square miles (0.04 km2), or 3.38%, is water.[4]