World Scrabble Championship 2018
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| World Scrabble Championship 2018 | |
|---|---|
| 23 October 2018 – 28 October 2018 | |
| Winner | Nigel Richards |
| Number of players | 75 |
| Location | England |
The Mattel World Scrabble Championship 2018 was a Scrabble tournament organised by Mattel and Mindsports Academy (MSA) to determine the world champion in English Scrabble held from 23 to 28 October 2018.
The event was split into two divisions according to players' World English-Language Scrabble Players' Association (WESPA) ratings; the top division comprised some 75 players. 35 games were played on the first four days, after which the top eight proceeded to a 3-game quarterfinals, with the winners advancing to a 5-game semifinals on the same day; the top two players, Nigel Richards and Jesse Day, played a best-of-five final the day after for the top prize of €10,000. Richards beat Day 3–1, becoming world champion for an unprecedented fourth time.
The main event was preceded by a Junior World Scrabble Championship that was won by Pakistani Moiz Ullah Baig.[1] The World Scrabble Championship 2018 took place at the Riveria International Centre in Torquay, Devon, England from 23 to 27 October, with the finals being held at a "clearview cube" in the Westfield Shopping Centre in London a day later, as part of Scrabble's 70th anniversary celebrations.[2][3] The prize fund for the tournament was £15,500.[4] There were also concurrent events played in five different languages including Catalan, Spanish, French, Norwegian, and German.[5]
