Número de Bingham

Se define de la siguiente manera:

${\displaystyle \mathrm {Bm} ={\frac {\text{Fuerzas cortantes}}{\text{Fuerzas viscosas}}}}$

Deducción

	1	2	3	4
Ecuaciones	${\displaystyle \mathrm {Bm} ={\frac {\tau \ (d\ L)}{\nu \ (\nu \ \rho )}}}$	${\displaystyle \nu ={\frac {d^{2}}{t}}}$	${\displaystyle \mu =\nu \ \rho }$	${\displaystyle u={\frac {L}{t}}}$
Sustituyendo	${\displaystyle \mathrm {Bm} ={\frac {\tau \ (d\ L)}{(d^{2}\ /\ t)\ (\mu )}}}$
Simplificando	${\displaystyle \mathrm {Bm} ={\frac {\tau \ L}{(d\ /\ t)\ \mu }}}$
Multiplicando ${\displaystyle {\Bigl (}{\frac {d\ L}{d\ L}}{\Bigr )}}$	${\displaystyle \mathrm {Bm} ={\Bigl (}{\frac {d\ L}{d\ L}}{\Bigr )}{\frac {\tau \ L}{(d\ /\ t)\ \mu }}}$
Simplificando	${\displaystyle \mathrm {Bm} ={\Bigl (}{\frac {L}{d}}{\Bigr )}{\frac {\tau \ L}{(L\ /\ t)\ \mu }}}$
Sustituyendo	${\displaystyle \mathrm {Bm} ={\Bigl (}{\frac {L}{d}}{\Bigr )}{\frac {\tau \ L}{u\ \mu }}}$

${\displaystyle \mathrm {Bm} ={\Bigl (}{\frac {L}{d}}{\Bigr )}{\frac {\tau \ L}{u\ \mu }}}$

• Número de Hedström