1807 Delaware gubernatorial election
From Wikipedia, the free encyclopedia
The 1807 Delaware gubernatorial election was held on October 6, 1807.[1] The Federalist senator from Kent County George Truitt defeated the Democratic-Republican candidate Joseph Haslet.[2]
October 6, 1807
| |||||||||||||||||
| |||||||||||||||||
Truitt: 50â60% 60â70% Haslet: 60â70% | |||||||||||||||||
| |||||||||||||||||
General election
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Federalist | George Truitt | 3,309 | 51.93 | ||
| Democratic-Republican | Joseph Haslet | 3,062 | 48.05 | ||
| Democratic-Republican | Richard C. Dale | 1 | 0.01 | ||
| Total votes | 6,372 | 100.00 | |||
| Federalist hold | |||||
Results by county
| County | George Truitt Federalist |
Joseph Haslet Democratic-Republican |
Richard C. Dale Democratic-Republican |
Margin | Total | ||||
|---|---|---|---|---|---|---|---|---|---|
| # | % | # | % | # | % | # | % | ||
| Kent | 1,088 | 53.3 | 952 | 46.7 | â | 136 | 6.6 | 2,040 | |
| New Castle | 580 | 31.7 | 1,249 | 68.2 | 1 | 0.0 | -669 | -36.5 | 1,830 |
| Sussex | 1,641 | 65.6 | 861 | 34.4 | â | 780 | 31.2 | 2,502 | |
| TOTAL | 3,309 | 51.9 | 3,062 | 48.0 | 1 | 0.0 | 247 | 3.9 | 6,372 |