1810 Delaware gubernatorial election
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The 1810 Delaware gubernatorial election was held on October 2, 1810.[1] The Democratic-Republican candidate Joseph Haslet defeated the Federalist former judge of the Delaware Court of Common Pleas Daniel Rodney.[2]
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October 2, 1810
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 Haslet: 60â70% Rodney: 50â60% 60â70% | |||||||||||||||||
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General election
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Democratic-Republican | Joseph Haslet | 3,664 | 50.49 |  2.44 | |
| Federalist | Daniel Rodney | 3,593 | 49.51 |  2.42 | |
| Total votes | 7,257 | 100.00 | |||
| Democratic-Republican gain from Federalist | |||||
Results by county
| County | Joseph Haslet Democratic-Republican |
Daniel Rodney Federalist |
Margin | Total | |||
|---|---|---|---|---|---|---|---|
| # | % | # | % | # | % | ||
| Kent | 1,049 | 46.2 | 1,221 | 53.8 | -172 | -7.6 | 2,270 |
| New Castle | 1,584 | 68.5 | 727 | 31.5 | 857 | 37.0 | 2,311 |
| Sussex | 1,031 | 39.7 | 1,645 | 60.3 | -614 | -20.6 | 2,676 |
| TOTAL | 3,664 | 50.5 | 3,593 | 49.5 | 71 | 1.0 | 7,257 |
