1816 United States presidential election in Delaware
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A presidential election was held in Delaware on November 12, 1816, as part of the 1816 United States presidential election.[1] The unpledged Federalist electoral candidates were selected by the Delaware General Assembly over the Democratic-Republican candidates, who were pledged to James Monroe.[2] The Federalist Party had failed to nominate a ticket prior to the election.[3] At the meeting of the electoral college, three of the four Delaware electors voted for the senior U.S. senator from New York Rufus King for president and the junior U.S. senator from Maryland Robert Goodloe Harper for vice president, while one elector did not vote.[4]
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November 12, 1816
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General election
Results
| Party | Candidate | Votes | |
|---|---|---|---|
| Federalist | Andrew Barrett | 18 | |
| Federalist | Thomas Robinson | 18 | |
| Federalist | Nicholas Ridgely | 18 | |
| Federalist | Isaac Tunnell | 18 | |
| Democratic-Republican | Manean Bull | 7 | |
| Democratic-Republican | Cornelius P. Comegys | 7 | |
| Democratic-Republican | George Reed | 7 | |
| Democratic-Republican | Henry M. Ridgely | 7 | |
Total |
25 | ||
Electoral college
| For President | For Vice President | ||||||
|---|---|---|---|---|---|---|---|
| Candidate | Party | Home state | Electoral vote |
Candidate | Party | Home state | Electoral vote |
| Rufus King | Federalist | New York | 3 | Robert Goodloe Harper | Federalist | Maryland | 3 |
| Not cast | 1 | Not cast | 1 | ||||
Total |
4 |
Total |
4 | ||||
See also
Notes
- One elector did not vote.
- Results of balloting in the Delaware General Assembly.