1816 United States presidential election in Georgia
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A presidential election was held in Georgia on November 12, 1816, as part of the 1816 United States presidential election.[1] The Democratic-Republican ticket of the U.S. secretary of state James Monroe and the governor of New York Daniel D. Tompkins received eight votes from electors chosen by the Georgia General Assembly.[2] The Federalist Party failed to nominate a candidate.[3] Monroe won the national election handily, defeating the senior U.S. senator from New York Rufus King, who received 34 votes from unpledged electors despite not being a candidate.[4]
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November 12, 1816
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General election
Results
| Party | Candidate | Votes | |
|---|---|---|---|
| Democratic-Republican | David Adams | ** | |
| Democratic-Republican | John Clark | ** | |
| Democratic-Republican | Charles Harris | ** | |
| Democratic-Republican | Jared Irwin | ** | |
| Democratic-Republican | John McIntosh | ** | |
| Democratic-Republican | David Meriwether | ** | |
| Democratic-Republican | Henry Mitchell | ** | |
| Democratic-Republican | John Rutherford | ** | |
Total |
** | ||
Electoral college
| For President | For Vice President | ||||||
|---|---|---|---|---|---|---|---|
| Candidate | Party | Home state | Electoral vote |
Candidate | Party | Home state | Electoral vote |
| James Monroe | Democratic-Republican | Virginia | 8 | Daniel D. Tompkins | Democratic-Republican | New York | 8 |
Total |
8 |
Total |
8 | ||||
See also
Notes
- Results of balloting in the Georgia General Assembly. The number of votes cast for each candidate is unknown.