1818 Rhode Island gubernatorial election
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The 1818 Rhode Island gubernatorial election was an election held on April 15, 1818, to elect the governor of Rhode Island. Nehemiah Rice Knight, the incumbent governor and Democratic-Republican nominee, beat Elisha Reynolds Potter, the Federalist candidate with 53.60% of the vote.
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April 15, 1818[1]
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 County results Knight: 50â60% 70â80% Potter: 50â60% 60â70% | |||||||||||||||||
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General election
Candidates
- Nehemiah Rice Knight, the incumbent governor since 1817.[2]
- Elisha R. Potter, member of the US House of Representatives for Rhode Island 1809â1815.[3]
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Democratic-Republican | Nehemiah Rice Knight (incumbent) | 4,509 | 53.7% | ||
| Federalist | Elisha Reynolds Potter | 3,895 | 46.3% | ||
| Majority | 614 | 7.3% | |||
| Democratic-Republican hold | Swing | ||||
County results
| County[4] | Nehamiah Knight
Democratic-Republican |
Elisha Potter
Federalist |
Total votes | ||
|---|---|---|---|---|---|
| # | % | # | % | ||
| Bristol | 261 | 55.3% | 211 | 44.7% | 472 |
| Kent | 601 | 49.3% | 617 | 50.7% | 1,218 |
| Newport | 774 | 38.5% | 1,228 | 61.5% | 2,002 |
| Providence | 2,108 | 70.9% | 866 | 29.1% | 2,974 |
| Washington | 765 | 44.0% | 973 | 56.0% | 1,738 |
| Totals | 4,509 | 53.7% | 3,895 | 46.3% | 8,404 |
