1819 Rhode Island gubernatorial election
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The 1819 Rhode Island gubernatorial election was an uncontested election held on April 21, 1819, to elect the governor of Rhode Island. Nehemiah Rice Knight, the incumbent governor and Democratic-Republican nominee, was the only candidate and so won with 100% of the vote.
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April 21, 1819[1]
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 County results Knight: 90â100% | |||||||||||||||||
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General election
Candidates
- Nehemiah Rice Knight, the incumbent governor since 1817.[2]
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Democratic-Republican | Nehemiah Rice Knight (incumbent) | 2,670 | 100% | ||
| Majority | 2,670 | 100% | |||
| Democratic-Republican hold | Swing | ||||
By county
| County[3] | Nehemiah Knight
Democratic-Republican |
|---|---|
| Bristol | 175 |
| Kent | 473 |
| Newport | 518 |
| Providence | 1,056 |
| Washington | 448 |
| Totals | 2,670 |
