1840 United States presidential election in Georgia
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A presidential election was held in Georgia on November 2, 1840 as part of the 1840 United States presidential election.[1] Voters chose 11 representatives, or electors to the Electoral College, who voted for President and Vice President.
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November 2, 1840
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 County Results
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Georgia voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Georgia by a margin of 11.56%. This would be the last time that Georgia did not vote for the incumbent Democratic president until 1964.
Results
| 1840 United States presidential election in Georgia[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Whig | William Henry Harrison of Ohio | John Tyler of Virginia | 40,339 | 55.78% | 11 | 100.00% | ||
| Democratic | Martin Van Buren of New York | Richard Mentor Johnson of Kentucky | 31,983 | 44.22% | 0 | 0.00% | ||
| Total | 72,322 | 100.00% | 11 | 100.00% | ||||
