1844 United States presidential election in Georgia
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A presidential election was held in Georgia on November 4, 1844 as part of the 1844 United States presidential election.[1] Voters chose 10 representatives, or electors to the Electoral College, who voted for President and Vice President.
November 4, 1844
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County Results
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Georgia voted for the Democratic candidate, James K. Polk, over Whig candidate Henry Clay. Polk won Georgia by a margin of 2.38%.
Results
| 1844 United States presidential election in Georgia[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 44,147 | 51.19% | 10 | 100.00% | ||
| Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 42,100 | 48.81% | 0 | 0.00% | ||
| Total | 86,247 | 100.00% | 10 | 100.00% | ||||