1846 Iowa gubernatorial election
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The 1846 Iowa gubernatorial election was held on October 26, 1846, in order to elect the first Governor of Iowa upon Iowa acquiring statehood on December 28, 1846. Democratic nominee Ansel Briggs defeated Whig nominee Thomas McKnight.[1]
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October 26, 1846
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 County results Briggs: 50â60% 60â70% 70â80% 80â90% McKnight: 50â60% 60â70% No Data/Votes: | |||||||||||||||||
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General election
On election day, October 26, 1846, Democratic nominee Ansel Briggs won the election by a margin of 247 votes against his opponent Whig nominee Thomas McKnight, thereby gaining Democratic control over the new office of Governor. Briggs was sworn in as the 1st Governor of the new state of Iowa on December 28, 1846.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Ansel Briggs | 7,626 | 50.82 | |
| Whig | Thomas McKnight | 7,379 | 49.18 | |
| Total votes | 15,005 | 100.00 | ||
| Democratic gain from Whig | ||||