1850 Iowa gubernatorial election

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The 1850 Iowa gubernatorial election was held on August 5, 1850.[1]

Quick facts Nominee, Party ...
1850 Iowa gubernatorial election
← 1846
August 5, 1850
1854 â†’
 
Nominee Stephen P. Hempstead James L. Thompson
Party Democratic Whig
Popular vote 13,486 11,403
Percentage 52.94% 44.76%
County results
Hempstead:      50–60%      60–70%      80–90%
Thompson:      40–50%      50–60%      80–90%
No Data/Votes:      
Governor before election

Ansel Briggs
Democratic

 Elected Governor

Stephen P. Hempstead
Democratic

Close

Incumbent Democratic governor Ansel Briggs declined to stand for re-election.[2][3]

Democratic nominee Stephen P. Hempstead defeated Whig nominee James L. Thompson and Free Soil nominee William Penn Clark with 52.94% of the vote.

General election

Candidates

  • William Penn Clark, Free Soil, lawyer, former newspaper editor[4][5]
  • Stephen P. Hempstead, Democratic, former president of the Iowa Territory Legislative Council[6]
  • James L. Thompson, Whig, Methodist preacher[7][8]

Results

More information Party, Candidate ...
1850 Iowa gubernatorial election[9][10][11][12][13][14][15][a]
Party Candidate Votes % ±%
Democratic Stephen P. Hempstead 13,486 52.94%
Whig James L. Thompson 11,403 44.76%
Free Soil William Penn Clark 575 2.26%
Scattering 11 0.04%
Majority 2,083 8.18%
Turnout 25,475
Democratic hold Swing
Close

Notes

  1. [a]
    Some sources give the result as Thompson's vote as 11,452.[16][17][18] The result given is taken from the Iowa Senate Journal.

References

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