1847 Tennessee gubernatorial election
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The 1847 Tennessee gubernatorial election was held on August 5, 1847, to elect the Governor of Tennessee. Whig nominee and former member of the Tennessee House of Representatives Neill S. Brown defeated Democratic nominee and incumbent Governor Aaron V. Brown.[1]
August 5, 1847
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County results S. Brown: 50â60% 60â70% 70â80% 80â90% V. Brown: 50â60% 60â70% 70â80% 80â90% No data/No votes | |||||||||||||||||
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Background
Aaron V. Brown, then governor of Tennessee, was closely connected with James K. Polk, his former law partner and friend, who had recently become President of the United States. When the MexicanâAmerican War began, Brown issued a call for 2,800 volunteer soldiers to serve in the conflict. Over 30,000 Tennesseans answered, solidifying the stateâs reputation as the "Volunteer State," a reputation first earned when citizens answered a similar call during the War of 1812.[2][3] While initially popular, support for the war gradually declined, and Brown was defeated in his re-election bid by Neill S. Brown (no relation) in 1847.[4]
General election
On election day, August 5, 1847, Whig nominee Neill S. Brown won the election by a margin of 1,368 votes against his opponent Democratic nominee and incumbent Governor Aaron V. Brown, thereby gaining Whig control over the office of Governor. Brown was sworn in as the 12th Governor of Tennessee on October 17, 1847.[5]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Whig | Neill S. Brown | 61,372 | 50.56 | |
| Democratic | Aaron V. Brown (incumbent) | 60,004 | 49.44 | |
| Total votes | 121,376 | 100.00 | ||
| Whig gain from Democratic | ||||