1849 Tennessee gubernatorial election
From Wikipedia, the free encyclopedia
The 1849 Tennessee gubernatorial election was held on August 2, 1849, to elect the Governor of Tennessee. Democratic nominee and Colonel in the US Army William Trousdale defeated Whig nominee and incumbent Governor Neill S. Brown by a slim margin.[1][2]
August 2, 1849
| |||||||||||||||||
| |||||||||||||||||
 County results Trousdale: 50â60% 60â70% 70â80% 80â90% Brown: 50â60% 60â70% 70â80% 80â90% 90â100% No Data/Vote: | |||||||||||||||||
| |||||||||||||||||
General election
On election day, August 2, 1849, Democratic nominee William Trousdale won the election by a margin of 574 votes against his opponent Whig nominee and incumbent Governor Neill S. Brown, thereby gaining Democratic control over the office of Governor. Trousdale was sworn in as the 13th Governor of Tennessee on October 16, 1849.[3]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | William Trousdale | 61,740 | 50.57 | |
| Whig | Neill S. Brown (incumbent) | 60,350 | 49.43 | |
| Total votes | 122,090 | 100.00 | ||
| Democratic gain from Whig | ||||