1884 United States presidential election in Minnesota
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The 1884 United States presidential election in Minnesota took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.
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November 4, 1884
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 County Results
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Minnesota was won by Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won the state by a margin of 21.91%.
With 58.78% of the popular vote, Minnesota would prove to be Blaine's second strongest victory in terms of percentage in the popular vote after Vermont.[1]
As of 2024, this remains the last time that a Republican presidential nominee would win a majority of the vote in Minnesota while losing nationally. This is also the first time since statehood that the state voted for the losing candidate.
Results
| 1884 United States presidential election in Minnesota[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | James Gillespie Blaine of Maine | John Alexander Logan of Illinois | 111,685 | 58.78% | 7 | 100.00% | ||
| Democratic | Grover Cleveland of New York | Thomas Andrews Hendricks of Indiana | 70,065 | 36.87% | 0 | 0.00% | ||
| Prohibition | John Pierce St. John of Kansas | William Daniel of Maryland | 4,684 | 2.47% | 0 | 0.00% | ||
| Greenback | Benjamin Franklin Butler of Massachusetts | Absolom Madden West of Mississippi | 3,583 | 1.89% | 0 | 0.00% | ||
| Total | 190,017 | 100.00% | 7 | 100.00% | ||||
