1888 United States presidential election in Minnesota

The 1888 United States presidential election in Minnesota took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.

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1888 United States presidential election in Minnesota

← 1884 November 6, 1888 1892 â†’

Nominee Benjamin Harrison Grover Cleveland Clinton Fisk Party Republican Democratic Prohibition Home state Indiana New York New Jersey Running mate Levi P. Morton Allen G. Thurman John A. Brooks Electoral vote 7 0 0 Popular vote 142,192 104,385 15,511 Percentage 54.12% 39.65% 5.82%

County Results Harrison   40–50%   50–60%   60–70%   70–80% Cleveland   40–50%   50–60%   60–70%   70–80%

President before election Grover Cleveland Democratic Elected President Benjamin Harrison Republican

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Minnesota voted for the Republican nominee, Benjamin Harrison, over the Democratic nominee, incumbent President Grover Cleveland. Harrison won the state by a margin of 14.47%.

With 5.82% of the popular vote, Minnesota would be the Prohibition Party candidate Clinton B. Fisk’s strongest victory in terms of percentage in the popular vote.^[1]