Delaware Township, Ripley County, Indiana

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CountryUnited States
Elevation928 ft (283 m)
FIPS code18-17524[2]
Delaware Township
Coordinates: 39°10′50″N 85°14′52″W / 39.18056°N 85.24778°W / 39.18056; -85.24778
CountryUnited States
StateIndiana
CountyRipley
Government
  TypeIndiana township
Area
  Total
33.27 sq mi (86.2 km2)
  Land33.21 sq mi (86.0 km2)
  Water0.06 sq mi (0.16 km2)
Elevation928 ft (283 m)
Population
 (2020)
  Total
1,513
  Density45.56/sq mi (17.59/km2)
Area code812
FIPS code18-17524[2]
GNIS feature ID453262

Delaware Township is one of eleven townships in Ripley County, Indiana. As of the 2020 census, its population was 1,513 (up from 1,437 at 2010[3]) and it contained 606 housing units.[4]

Historical population
CensusPop.Note
18901,214
19001,2140.0%
19101,095−9.8%
19201,001−8.6%
1930925−7.6%
19409593.7%
19501,05710.2%
19601,009−4.5%
19701,0271.8%
19801,18115.0%
19901,2505.8%
20001,2983.8%
20101,43710.7%
20201,5135.3%
Source: US Decennial Census[5]

Unincorporated towns

According to the 2010 census, the township has a total area of 33.27 square miles (86.2 km2), of which 33.21 square miles (86.0 km2) (or 99.82%) is land and 0.06 square miles (0.16 km2) (or 0.18%) is water.[3]

Education

References

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